3x^2+13x-10=10

Solution for 3x^2+13x-10=10 equation:

3x^2+13x-10=10

We move all terms to the left:

3x^2+13x-10-(10)=0

We add all the numbers together, and all the variables

3x^2+13x-20=0

a = 3; b = 13; c = -20;
Δ = b2-4ac
Δ = 132-4·3·(-20)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{409}}{2*3}=\frac{-13-\sqrt{409}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{409}}{2*3}=\frac{-13+\sqrt{409}}{6}
$